C - Write a C program to check whether a number is even or odd.

 

Question:

Write a C program to check whether a number is even or odd.

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Answer:

PROGRAM

  

#include <stdio.h>
int main()
{
    int number;

    printf("Enter an integer: ");
    scanf("%d", &number);
    if(number % 2 == 0)
        printf("\nThe number %d is even.", number);
    else
        printf("\nThe number %d is odd.", number);

    return 0;
}

Program Working:

Its a simple and easy to understand program code. I'll explain it step by step, so u can easily understand the working.

* An integer variable 'number' is declared to store the user input.

* User is asked to input an integer number to check whether it is an even or odd number.

* The user input is read from the keyboard and is stored into the variable number using scanf statement.

* Even numbers are divisible by 2. So to check whether a number is even , the number is divided by 2 and the remainder is obtained. If the remainder is 0 (zero) , the number is even. Else the number is odd. 

So to do this C language uses an operator % (modulus or modulo division) which gives the remainder of a division. So the number given by the user is divided by 2 and the remainder is checked.

If the remainder is equal to 0, the program prints the number is even

* If remainder is not 0, the program prints the number is odd.

* The program stops.